BM6500 / 7000 Powerlink – Attenuated Speaker or True Pre-Amp Out?

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  • #54008
    machineage
    BRONZE Member
      • Topics Started 1
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      Hi all!

      Can anyone tell me if the Powerlink audio outputs on the Beomaster 6500 & 7000 are attenuated speaker outputs, or are they true pre-amp outputs? Thanks!

      beomaster-7000

      #54009
      Guy
      Moderator
        • Warwickshire, UK
        • Topics Started 15
        • Total Posts 1,270

        Hi and welcome to Beoworld!

        I had a look at the circuit diagram (available to paid members) and the Powerlink Outputs are taken from the pre-amp stage (after input select, vol/tone control and muting). They do not go through the ‘Output Amplifier’ which supplies the speaker outputs.

        #54010
        machineage
        BRONZE Member
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          Thanks!

          I just found the schematic, and yes I see now, the pre-amp outputs are fed through 100Ω resistors to pins 3 & 5 of the Powerlink sockets.

          #54012
          Ninni
          BRONZE Member
            • Topics Started 3
            • Total Posts 24

            It’s probably to prevent external loads from affecting normal operation of the internal power amp (and speakers connected to it).

            #54011
            trackbeo
            BRONZE Member
              • Topics Started 8
              • Total Posts 253

              Novice question for the electronic experts here: Why the 100Ω resistors? Safety load to prevent shorting? Impedance matching, i.e. a dup of some 100Ω later in the amp circuit? IOW, what differentiates the amp next-door in the chassis from an amp down a few meters of cable inside the speakers? When running line-level output around the room, why would one reduce the already-low output? For that matter, I guess the same question is why you can’t hear the plugging-in of Powerlink speakers dropping the volume level to the main out speakers. Basic I’m sure, and I heard “output impedance low –> input impedance high” for line-level amps, but don’t *truly* grok else I might understand the resistors… TIA.

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